jQuery.isFunction() in JQuery


Description: Determine if the argument passed is a Javascript function object.

  • version added: 1.2jQuery.isFunction()

Note: As of jQuery 1.3, functions provided by the browser like alert() and DOM element methods like getAttribute() are not guaranteed to be detected as functions in browsers such as Internet Explorer.


Example: Test a few parameter examples.

<!DOCTYPE html>
  div { color:blue; margin:2px; font-size:14px; }
  span { color:red; }
  <script src="/scripts/jquery-1.4.js"></script>
  <div>jQuery.isFunction(objs[0]) = <span></span></div>

  <div>jQuery.isFunction(objs[1]) = <span></span></div>
  <div>jQuery.isFunction(objs[2]) = <span></span></div>
  <div>jQuery.isFunction(objs[3]) = <span></span></div>

  <div>jQuery.isFunction(objs[4]) = <span></span></div>
    function stub() {
    var objs = [
          function () {},
          { x:15, y:20 },

    jQuery.each(objs, function (i) {
      var isFunc = jQuery.isFunction(objs[i]);



Example: Finds out if the parameter is a funcion.


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